Hello Shawn , yes regarding biasing i put the resistor and voltage source as shown bellow and it worked fine. But when i will need to find the output impedance (for bandwith manipulation) then AC_resistance =1M will cause a problem. So for this purpose i have added a branch in parralel an I_AC=1A source as shown in the plot bellow Z=V_ac/I_ac I_ac=1 Z=V_ac and calculated the imaginary part of the Voltage that it sees and extracted the capacitance from it as shown bellow. 1/(2pi*100*(10^6)*x)=49000 x≈3.24806006309990×10^-14 But when i tried to reduce the bandwidth by adding an 1n capacitor in series it hasn't changed at all. Why my idial AC current source didnt see that the capacitance change. it gives me the same Imaginary part plot as before. Where did i go wrong ? AC Source: Ressistor for Impedance calculation: AADDING CAPACITOR TO MANIPULATE BANDWIDTH:
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